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#1 |
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If BYU beats Utah, who wins the tiebreaker? Is it the league champion or the highest in the BCS standings who would go to a BCS game (assuming they beat out BSU)? Can two non-BCS teams go if they're both in the top 16?
As a sidenote, if BYU does beat Utah (and of course AFA), then they'd have a pretty good claim to being the best, as among the top 3, as they were 1-1 with both games on the road. It would be: 1) BYU (both road) 2) TCU (one road, one away) 3) Utah (both home games) Kind of a funny reversal of popular opinion right now, although based on last night's performance (and an application of Bayes theorem), I'm not convinced Utah's better than TCU. |
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#2 | |
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LINCECUM! |
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#3 | |
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#4 |
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I'll answer my own question here. It does appear that there can be two "BCS busters" in the same year. From the wikipedia entry:
"The highest ranked champion of a non-BCS conference will receive an automatic berth if: It is ranked in the top twelve, or Ranked in the top sixteen and higher than another BCS Conference champion. " http://en.wikipedia.org/wiki/Bowl_Championship_Series I could actually see both BSU and BYU/Utah/TCU making BCS games this year. Am I reading this wrong? |
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#5 | |
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#6 | |
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Its all about the suit |
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#7 |
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Is any of the three teams legitimately BCS ready?
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#8 |
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#9 |
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#10 |
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