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Old 09-08-2008, 04:34 PM   #70
Jeff Lebowski
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Join Date: Jan 2006
Location: In the heart of darkness (Provo)
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Quote:
Originally Posted by ERCougar View Post
Oh yeah? Watch this:

Total time is 2.36 seconds. One-half of that is the time to get to its peak height - 1.18 secs. Gravity deceleration is 32 ft/sec/sec.
Initial velocity = 32 ft/sec/sec * 1.18 secs = 37.76 ft/sec.
Peak height = Initial height + (Initial velocity * time to peak) - (1/2 * 32 ft/sec/sec * time ^2)
=6 + (37.76*1.18) - (16*1.18 ^2)
=6 + 44.56 - 22.28
=28.28 ft

Spreadsheets are for sissies.
Having not watched the video showing the full trajectory, I assumed that the ball returned to the ground, not to his helmet. In which case, the 2.36 seconds is total time in the air, involving an asymmetric parabolic arc, and more complicated math than that sissy stuff you just posted via cut-and-paste.

Neener neener.
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